Laserfiche WebLink
Fovenumina <br />4.833 ft -� <br />3.222 ft <br />V Base Shear <br />Oil Stop <br />309 W- Kettleman Lane <br />Lodi, CA 95240 <br />3.58 it <br />4.833 ft <br />Attachment D <br />Waste Oil Tank <br />(Normal Operation <br />Wt tank run= <br />Wt tank empty= <br />Wt Liquid= <br />Hank= <br />Governing Wank= <br />H;puld <br />hoTM= <br />Arm; <br />Armt= <br />Tank Length (long)= <br />Tank Width (short)= <br />Distance (A to B)= <br />F,nnchor Pup Out= <br />Information <br />- Short! <br />8697 <br />lbs <br />lbs <br />1100 <br />7597 <br />lbs <br />4.8333 <br />ft <br />3.583 <br />ft <br />4.8333 <br />ft <br />3.222 <br />ft <br />ft <br />ft <br />ft <br />1.050 <br />1.050 <br />8.333 <br />3.583 <br />ft <br />ft <br />lbs <br />2.932 <br />2400 <br />1 Calculate Overturning & Resisting Moments <br />MOT = FOT(hOTM)= 3.222 xFOT <br />MR = Wttank empty x Arm, + WtLigt,;o x Army= 7,597 x 1.050 + 1,100 x 1.050 = 9,128 ft -lbs <br />2. Set Mr,T = MR <br />3.222 FOT = 9,128 <br />FOT = 9,128 / 3.222 = <br />3. Calculate Lateral Seismic Force <br />V = 0.30 x Sos x W(tank full) x le <br />V= 0.30 x 0.611 x 8,697 x 1.25 = <br />Fx = Cvx x V and Cvx = Wx x hxK Wi x h K) <br />Taoorox=Ct x hnx <br />Ct = 0.02 <br />X = 0.75 <br />Taoorox=Ct x hnx = 0.02 x (4.833) 1.15 <br />2,833 lbs <br />Base Shear (ASCE 7-10, 15.4.2) <br />Ibs <br />Lateral Seismic Force (ASCE 7-10, 12.8.3) <br />Fundamental Period (ASCE_ 7-10, 12.8.2.1) <br />(ASCE 7-10, Table 12.8-2) <br />(ASCE 7-10, Table 12.8-2) <br />= 0.065 s < 0.5 s K= 1.00 <br />Cvx = Wx x hxK / (I Wi x hK) = 8,697 x 3.222^1 /(1,100 x 3.222^1 + 7,597 x 3.222^1)= 1.00 <br />Fx = Cvx x V = 1.00 x 1,993 = 1993 Fot > F. <br />Tank is Stable <br />4. Calculate Safetv Factor <br />SF = Fot / Fx = 2,833 / 1,993 = 1.42 < 2.5 N.G. <br />Re -calculate Overturning & Resisting Moments with Tank Anchorage <br />MOT = FOT(hOTM)= 3.222 xFOT <br />M,t = Wttn„ k,mptyx Armt+ WtL,y,,;d x Armu + Fa„,h,,, x ArmA= 7,597 x 1.050 + 1.100x 1.050 + 2,400 x 2.932 = <br />Set M„T = MR <br />3.222 FOT = 16,164 <br />FOT = 16,164 / 3.222 = <br />55afety Factor with Anchorage <br />SF = Fot / Fx = 5,017 / 1,993 = <br />5 Calculate Resistance to Sliding without Anchors <br />V < W tan 30° = 8,697 x tan 30° = <br />5,017 Ibs <br />2.52 > 2.5 OK <br />5021 > Base Shear <br />Tank does not Slide <br />FSeismic/Anchoring Findings: The tank as designed and operated, and the containment area in which it <br />located proved to be seismically sound. <br />16,164 ft-Ibs <br />