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T <br /> Nutrient Value Calculation: <br /> 1 . 40,000 gls Water in Tank = 8.33 #/gl X 40,000 gls = 333,200# Water <br /> 2. Of the total amount of Phosphoric Acid (70% Phosphorous) spilled (300 gallons), assume 314 remained in Water <br /> 300 gls Phos Acid x .7 x 14$Pgl x .75 = 2205# Phosphorous <br /> 3. 3740# of Aqueous Ammonia (20% Nitrogen) added to Water to raise pH (Weight Tag in file) <br /> 3740# x 20% Nitrogen = 748# Nitrogen <br /> Nitrogen Content: 748# Nitrogen 1 333,200# Water = .0022 = .220/c Nitrogen <br /> Phosphorous Content; 2205# Phosphorous/ 333,204#Water = .0066 = .660A Phosphorous <br />