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II - <br /> N <br /> APPENDIX D <br /> DISSOLVED TPH -g VOLUME ASSUMPTIONS AND CALCULATIONS <br /> PAGE 3OF8 <br /> Water occupies the porosity in the soil , which is estimated to be 30% of the soil volume, so the <br /> total volume of water in the saturated portion of the ellipse is approximated by: <br /> V1o.000 = (0 .30 )(61300 ft3) = 13890 ft3 <br /> One ft3 is equal to 7 .48 gallons , so the volume of the water in the ellipse is given by: <br /> V1o,o❑0 = ( 1 ,890 ft3)(7.48 gal/ft3) = 14, 137 gallons <br /> One gallon of water is equivalent to 3 . 79 liters (/), so the volume water is given by: <br /> V1o,000 = ( 14, 137 gallons )(3 .79 //gal) = 53 ,580 / water <br /> Multiplying the volume of water by the average dissolved TPH-g concentration (48, 667 pg/I) yields <br /> the approximate mass of TPH-g in groundwater: <br /> V110,o00 = (53580 1) (0 .000048667 kg/1) = 2 .6 kg TPH-g <br /> A conversion factor of 2.205 Ib/kg . can be used to convert kilograms of TPH-g to pounds of <br /> TPH-g : <br /> MTPH-0 = (2 . 6 kg TPH-g)(2 .205 Ib/kg ) = 5.7 lbs . TPH -g <br /> Dividing M10,000 by the weight of one gallon of TPH-g , 6 . 25 lbs/gallon , will yield the approximate <br /> volume of TPH-g dissolved into the groundwater of the middle contour interval : <br /> V10,000 = (M10,000)/6 .25lb/gal ) = 5.7 lbs ./6 .25 lbs/gal = 0 .9 gallons of dissolved TPH-g <br /> 3) For the estimated 1 ,000 pg/I middle contour interval , A1000 = 736 ft' , h = 22 ft (average <br /> thickness) <br /> Utilizing the 10 , 000 pg/I contour line and the 1 , 000 pg/I , the average TPH-g concentration is <br /> estimated to be 5 , 500 ug/1 (equivallant to 0 . 0000055 kg/1) . <br /> Area : A1 ,ow = 736 ft2 <br /> The volume is given by: V1 000 = V1000 -Vt00❑❑ x h = 91452 ft' <br /> Water occupies the porosity in the soil , which is estimated to be 30% of the soil volume, so the <br /> total volume of water in the saturated portion of the ellipse is approximated by: <br /> I <br /> V1,. = (0 .30)(9 ,452 ft3) = 2 ,836 ft3 <br /> One ft3 is equal to 7.48 gallons , so the volume of the water in the ellipse is given by: <br /> V1000 = (2 ,836 ft3)(7.48 gal/ft3) = 21 ,210 gallons <br /> One gallon of water is equivalent to 3 . 79 liters (/) , so the volume water is given by: <br />