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I <br /> APPENDIX D <br /> DISSOLVED TPH -g VOLUME ASSUMPTIONS AND CALCULATIONS <br /> PAGE 6 OF 8 <br /> Dividing M100,000 by the weight of one gallon of TPH-g , 6 .25 lbs/gallon , will yield the approximate <br /> volume of TPH-g dissolved into the groundwater of the inner contour interval : <br /> V1001000 = (M100,000)/6. 25 Ib/gal) = 6.4 lbs./6 .25 lbs/gal = 1 .0 gallons of dissolved TPH-g <br /> 2 ) For the estimated 10 , 000 pg/I middle contour interval , A10,000 = 1 , 909 ft" h = 25 ft (average <br /> thickness) <br /> Utilizing boring CPT1 ( 16 , 000 pg/1 ) , and well MW-7 (12 , 000 pg/1 ) and the 100,000 pg/I contour line <br /> and the 10 , 000 pg/I (Figure 13) , the average TPH-g concentration is estimated to be 34, 500 ug/I <br /> (equivalent to 0 . 0000345 kg/1). <br /> Area: A10,000 = 1 , 909 ftz <br /> The volume is given by: V10o00 = V10,000 -V10a,Ooox h = 44 ,758 ft3 <br /> Water occupies the porosity in the soil , which is estimated to be 30% of the soil volume , so the <br /> total volume of water in the saturated portion of the ellipse is approximated by: <br /> V101000 = (0 .30)(44,758 ft) = 13,427 ft3 <br /> One ft3 is equal to 7 .48 gallons, so the volume of the water in the ellipse is given by: <br /> V10,000 = (13,427 ft)(7 .48 gal/ft3) = 100 ,437 gallons <br /> One gallon of water is equivalent to 3. 79 liters (/) , so the volume water is given by: <br /> V,%O0o = (100 ,437 gallons)(3 .79 //gal) = 380 ,6561 water <br /> Multiplying the volume of water by the average dissolved TPH-g concentration (34 ,500 pg/1) yields <br /> the approximate mass of TPH-g in groundwater: <br /> V110,000 = (380,656 /) (0 .0000345 kg//) = 13. 1 kg TPH -g <br /> A conversion factor of 2.205 Ib/kg . can be used to convert kilograms of TPH-g to pounds of <br /> TPH-g : <br /> MTP„-9 = ( 13 . 1 kg TPH-g )(2.205 Ib/kg) = 28.9 lbs. TPH-g <br /> Dividing M10,000 by the weight of one gallon of TPH-g , 6 .25 lbs/gallon , will yield the approximate <br /> volume of TPH-g dissolved into the groundwater of the middle contour interval : <br /> V101000 = (M10,000)/6 .25lb/gal) = 28.9 lbs./6.25 lbs/gal = 4. 6 gallons of dissolved TPH-g <br /> 3) For the estimated 1 ,000 pg/I middle contour interval , Al , 000 = 3,434 ftz, h = 25 (average <br /> thickness ) <br />