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ARCHIVED REPORTS XR0000659
EnvironmentalHealth
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CAPITOL
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6421
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2900 - Site Mitigation Program
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PR0522496
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ARCHIVED REPORTS XR0000659
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Entry Properties
Last modified
2/15/2019 9:22:49 PM
Creation date
2/15/2019 3:11:18 PM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0000659
RECORD_ID
PR0522496
PE
2957
FACILITY_ID
FA0015317
FACILITY_NAME
FLAG CITY CHEVRON
STREET_NUMBER
6421
STREET_NAME
CAPITOL
STREET_TYPE
AVE
City
LODI
Zip
95245
APN
05532024
CURRENT_STATUS
02
SITE_LOCATION
6421 CAPITOL AVE
P_LOCATION
99
P_DISTRICT
004
QC Status
Approved
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EHD - Public
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! FLAG CITY CHEVRON <br /> Ground Water Pump Test Calculations <br /> w � <br /> Assumptions: <br /> r <br /> • Pump Test No.`1: extraction from EW-2 at constant ground water pumping rate of 4.0 GPM <br /> �- • Pump Test No. 2: extraction from EW-2 at constant ground water pumping rate of 6.6 GPM <br /> • ground water Pump <br /> Pump Test No.3: extraction from EW-2 at constant Pumping rate of 10.0 GPM <br /> • Pump Test No.4: extraction from EW-3 at constant <br /> ground water pumping rate of.10.0 GPM <br /> • The Jacobs Straight Line Method (Distance-Drawdown Method) can be utilized to <br /> calculate transmissivity(T) and specific yield utilizing draw-down versus distance on semi- <br /> F: logarithmic paper for each well location(Appendix F). <br /> T=transmissivity; S =specific yield <br /> Q=constant ground water pumping rate. <br /> 4s=draw-down per I-logarithmic cycle. <br /> t=time of pump test <br /> Fr9=intercept of best fit line with the distance axis <br /> FPump Test No. 1: Q = 4.0 GPM; As = 2.7 ft.; t= 60 minute• r — 1 <br /> f� © 7 ft. 1 <br /> T=70Q=Q s -4 70(4.0 GPM) �2.7 ft=104 fe/day <br /> r T= 104 ff2/day x I gpd/ft_ 0.134 fl/day=774 gpd/ft <br /> S = T(t)� 640 (ro)2 = (104 ft2/da 60 min — 640 17 2 — <br /> Y){ ) � ( ){ ) —0.034 <br /> Pum — <br /> Pump Test No. 2. Q = 6.6 GPM; As = 4.8 ft.; t= 600 minute; ro = 20.5 ft. <br /> T=70Q-as -+ 70(6.6 GPM) 4.8 ft=96.25 ft/day <br /> T =96.25 ft/day x 1 gpd/ft 0.134 ftz/day-=718 gpd/ft <br /> S =T(t) -640 (ro)2= (96.25 fl/day)(600 min)=(640)(20.5)2 =0.21 <br /> i Pum Test No. 3: } <br /> P Q = 10.0 GPM, As = 6.3 ft., t= 1.00 minute; ro = 24 ft. <br /> T=70Q--As -4 70(10.0 GPM) �6.3 ft= I11 ft2/day <br /> T= Ill ftz/day x 1 gpd/ft-0.134 fl/day=829 gpd/ft <br /> S =T(t) _640 (ro)2= (111 ft /day)(100 Iain) (640)(24)2 =0.03 <br /> w <br />{ <br /> Pump Test No. 4: Q = 10.0 GPM; As = 3.8 ft.; t= 400 minute; ro = 33 ft. <br /> T= 70Q=0s -+ 70(10.0 GPM) � 3.8 ft= 184 ftZ/day <br /> �. T= 184 ft2/day x 1 gpd/ft_ 0.134 ft/day= 1;375 gpd/ft <br /> S = T(t) _ 640 (ro)2 = (184 ft2/day)(400 min)_ (640)(33)2 <br /> Advanced GeoEnvironmental,Inc. <br />
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