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Mass-Volume Calculation of Dissolved MTBE - 14 April to 13 May 2004 <br /> FLAG CITY CHEVRON- 6421 Capitol Avenue, Lodi, CA <br /> Assumptions <br /> • A total volume of 325,552 gallons was continuously extracted from wells EW-4, EW-5, <br /> EW-7, EW-8 and EW-10 between 14 April to 13 May 2004 (based on effluent flow meter <br /> y observations) <br /> • Data collected from the puinp and treat influent water samples were representative of general <br /> extracted ground water conditions <br /> One gallon of water is equivalent to 3 79 liters, so the volume of processed water is given by <br /> V= (325,552 gallons)(3 79 1/gal) = 1,233,8421 processed water <br /> Multiplying the volume of the processed water by the average of the April 2004 and the May 2004 <br /> MTBE concentrations (17 5 µg/1) yields the approximate mass of MTBE removed from processed <br /> water <br /> MMTBE=(1,233,8421)(0 0000000175 kg/l)= 0.022 kg MTBE (approx 22 grams) <br /> A converstion factor of 2 205 lb/kg can be used to convert kilograms of MTBE to pounds of MTBE <br /> MMTBE — (0 022 kg MTBE)(2 205 lb/kg) = 0.05 lb MTBE <br /> Advanced GeoEnvironmental,Inc <br />