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' Mass-Volume Calculation of Dissolved MTBE - 13 June 2002 to 29 Jul <br /> • y 2002 <br /> FLAG CITY CHEVRON - 5421 Capitol Avenue, Lodi, CA <br />' Assumptions <br />' • A total volume of 689,487 gallons was extracted from wells EW-4,EW-5,EW-9 and EW-10 <br /> between 13 June 2002 and 29 July 2002 (based on effluent flow meter observations) <br />' • Data collected froze the pump and treat Influent grab ground water samples were <br /> representative of general extracted ground water conditions <br />' One cubic foot of water contains 7 48 gallons, conversely, one gallon of water Is equivalent to <br /> 0 1337 cubic feet, so the volume of processed water is given by <br />' V= (689,487 gallons)(0 1337 ft3/gal) — 92,184 ft'processed water <br />' One gallon of water weighs 8 337 lbs/gal at 60°F, so the mass of processed water is given by <br /> M,,a,_ (689,487 gallons)(8 337 lbs /gal) =5,748,253 lbs. processed water <br />' Multiplyingthe mass of the processed water bythe averageMTBE concentration(06-13-02=19gg/L <br /> and 07-29-02 = 17 jig/L, avg = 18 gg/L) yields the approximate mass of MTBE removed from <br /> lie processed water <br /> MMTBE = (5,748,253 lbs)(0 0000000 18) = 0.10 lbs MTBE <br /> A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to kilograms of <br /> MTBE <br /> MMTBE = 0 10 lbs MTBE (0 4536 kg/lb) =45 g of MTBE <br /> I <br /> Advanced GeoEnvironmental,Inc <br />