Laserfiche WebLink
' Mass-Volume Calculation of Dissolved MTBE - 27 August 200 <br /> • g 2 to 45 September 2002 <br />' FLAG CITY CHEVRON - 6421 Capitol Avenue, Lodi, CA <br /> Assumptions <br />' • A total volume of 193,763 gallons was extracted from wells EW-4,EW-5,EW-8 and EW-10 <br /> between 27 August and 05 September 2002 (based on effluent flow meter observations) <br />' • Data collected from the pump and treat influent and extraction well-head grab ground water <br /> samples were representative of general extracted ground water conditions <br />' One cubic foot of water contains 7 48 gallons, conversely, one gallon of water is equivalent to <br /> 0 1337 cubic feet, so the volume of processed water is given by <br /> 1 V=(193,763 gallons)(0 1337 ftp/gal) =25,906 W processed water <br />' One gallon of water weighs 8 337 lbs/gal at 60°F, so the mass of processed water is given by <br /> Mwater= (193,763 gallons)(8 337 lbs /gal) = 1,615,402lbs. processed water <br />' Multiplying the mass of the processed water by average e MTBE concentration 08-27-02= <br /> g <br /> 9 7gg/l, 09-05-02=9 1 µg/1, avg =9 4 µg11) yields the approximate mass of MTBE removed from <br /> fprocessed water <br /> MMTBE= (1,615,402 lbs)(0 0000000094) = 0 02 lbs MTBE <br /> A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to grams of MTBE <br /> rMMTBE= 0 02 lbs MTBE (0 4536 kg/lb) = 9 g of MTBE <br /> I <br /> Advanced GeoEnvironmcntal,Inc <br />