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Mass-Volume Calculation of Dissolved MTBE - 14 May to 25 June 2003 <br /> FLAG CITY CHEVRON- 6421 Capitol Avenue, Lodi, CA <br /> Assumptions <br /> I • A total volume of 1,144,208 gallons was extracted from wells EW-4, EW-5, EW-7 and <br /> EW-8 between 24 February and 25 March 2003 (based on effluent flow meter observations) <br /> • Data collected from the pump and treat influent water samples were representative of general <br /> extracted ground water conditions <br /> One gallon of water weighs 8 337 lbs/gal at 60° <br /> F, so the mass of processed water is given by <br /> M,,,^ (1,144,208 galions)(8 337 lbs/gal) =9,539,262 lbs. processed water <br /> Multiplying the mass ofthe processed water by the average MTBE concentration(05-14-03=371Cg/L <br /> and 06--25-03 = 17 gg/L, avg = 27 gg/L) yields the approximate mass of MTBE removed from <br /> processed water <br /> M,4.mp =(9,539,2621bs)(0 000000027) = 0.26 lbs MTBE <br /> A converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to grams of MTBE <br /> MMTBE = 0 26 lbs MTBE (0 4536 kg/lb) = 118 g of MTBE <br /> r <br /> i <br /> i <br /> Advanced GeoEnvironmental,Inc <br /> I <br />