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. Mass-Volume Calculation of Dissolved MTBE - 01 August 2001 to 06 September 2001 <br />' FLAG CITY CHEVRON- 6421 Capitol Avenue, Lodi, CA <br /> Assumptions <br /> • A total volume of 440,035 gallons was extracted from wells EW-2, EW-4, EW-5, EW-6, <br /> EW-7, EW-8, EW-9 and EW-10 between 01 August and 06 September 2001 (based on <br />' effluent flow meter observations between 01 August and 06 September 2001) <br /> • Data collected from the pump and treat influent and extraction well-head grab ground water <br />' samples were representative of general extracted ground water conditions <br /> One cubic foot of water contains 7 48 gallons, conversely, one gallon of water is equivalent to <br />' 0 1337 cubic feet, so the volume of processed water is given by- <br /> V= (440,035 gallons)(0 1337 ft /gal) =58,833 ftp processed water <br /> One gallon of water weighs 8.337 lbs/gal at 60'F, so the mass of processed water is given by <br />' M—t,=(440,035 gallons)(8.337 lbs/gal) =3,668,572 lbs. processed water <br /> Multiplying the mass of the processed water by the average MTBE concentration(08-0 1-0 1= 19,ug/L <br /> and 09-06-01 = 7 ,ug(L, avg = 13 ,ug/L) yields the approximate mass of MTBE removed from <br /> processed water <br /> MmmF_(3,668,572 lbs)(0 000000013) = 0.051bs MTBE <br /> IA converstion factor of 0 4536 kg/lb can be used to convert pounds of MTBE to grams of MTBE <br /> MmTBz = 0 05 lbs MTBE (0 4536 kg/lb) =23 g of MTBE <br /> I <br /> IAdv,&&"d CeoEnvironmental,Yne. <br />