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i <br /> MASS-VOLUME CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> CONTINUED <br /> 28 February to 08 March 2000 <br /> The average analytical TPH-g concentration for dus time interval was determined to be 410,ug/l The average <br /> flow rate was calculated at 0 12 inches of water or approximately 19 cubic feet per minute, the operational <br /> period was equal to 216 hours of running time <br />' C = 410 gg/1=0 000410 kg/m' <br /> Q = 0 12 inches water = 19 ftp/min <br /> t=216 hours <br />' Converting Q to m'/hour yields Q=(19 ft'/min) -(60 mm/hour)-(0 0283168m'/ft3)= 32 28&/hour <br />' M =C - Q -t=(0 000410 kg/m')-(32 28&/hour) - (216 hours)=2 86 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br />' 2 86 kg of gas - 2 2046 lbs of gas/kg of gas =6 30 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br />' 6 30 lbs of gas - 0 16 gal of gas/lbs of gas = 1 gallon of gasoline <br /> M8 March to 29 March 2000 <br /> 3) The average TPH-g concentration for this time interval was calculated to be 290,ug/l The average flow rate <br />' was calculated at 0 21 inches of water or approximately 26 cubic feet per minute, the operational period was <br /> equal to 504 hours of running time <br />' C = 290,ug/l=0 000290 kg/m' <br /> Q = 0 21 inches water = 26 ft' <br /> /nun <br /> t=504 hours <br />' Converting Q to m'/hour yields Q =(26 ft'/nun) -(60 min/hour)-(0 0283I68m'/ft') =44 17 m'/hour <br /> M =C - Q - t=(0 000290 kg/m')-(44 17 m'/hour) - (504 hours)=6 46 kg of gasoline <br />' Converting kg of gasoline to pounds of gasoline yields <br />' 6 46 kg of gas - 2 2046 lbs of gas/kg of gas = 14 23 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br />' 14 23 lbs of gas - 0 16 gal of gas/lbs of gas =2 3 gallons of gasoline <br /> I <br /> I <br />