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FIELD DOCUMENTS 2002 - 2013
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3500 - Local Oversight Program
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PR0544497
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FIELD DOCUMENTS 2002 - 2013
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Last modified
5/28/2019 2:46:52 PM
Creation date
5/28/2019 2:32:46 PM
Metadata
Fields
Template:
EHD - Public
ProgramCode
3500 - Local Oversight Program
File Section
FIELD DOCUMENTS
FileName_PostFix
2002 - 2013
RECORD_ID
PR0544497
PE
3528
FACILITY_ID
FA0003687
FACILITY_NAME
OLD TRUCK STOP, THE
STREET_NUMBER
3535
STREET_NAME
CHEROKEE
STREET_TYPE
RD
City
STOCKTON
Zip
95205
APN
13206009
CURRENT_STATUS
02
SITE_LOCATION
3535 CHEROKEE RD
P_LOCATION
99
P_DISTRICT
002
QC Status
Approved
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EHD - Public
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I <br /> APPENDIX C <br /> VOLUME-MASS CALCULATIONS OF EXTRACTED GASOLINE HYDROCARBONS <br /> CHEROKEE TRUCK STOP <br /> .3535 East Cherokee Road, Stockton, California <br /> Assumptions: <br /> • Utilizing High Vacuum SVE pilot test analytical data collected from soil vapor <br /> samples (Table 2) and from field measurements collected during the pilot test <br /> (Table 1), the volume and mass of extracted gasoline hydrocarbons at the site can <br /> be approximated. <br /> The hydrocarbon volume-mass removed during the operating g period can be calculated <br /> using the following equation: f <br /> {� M = C • Q • t <br /> where: M = cumulative mass recovered (kg) <br /> C = vapor concentration (kg/m3) <br /> Q = extraction flow rate (M3/hr) <br /> t = operational period (hrs) <br /> The average InfluentTPH-g concentration and average flow rates during each time interval <br /> were utilized for calculating the approximate mass/volume of extracted gasoline <br /> hydrocarbons. <br /> 18 February 2010 M <br /> The average analytical TPH-g concentration for this time interval was determined to be ` <br /> (10:00 = 34,000 pg/I , 13:00 = 28,000 pg/1 and 16:00 28,000 pg/1) averaged = 30,000 <br /> Ng/l. <br /> E <br /> The average flow rate was calculated at 34.5cubic feet per minute; the operational period <br /> was equal to 8 hours of running time. <br /> C = 30 000 - 3 t <br /> Ng/I - 0.03 kg/m <br /> Q = 45 ft3/rein E <br /> t = 8 hours <br /> Converting Q to m3/hour yields: <br /> y <br /> Q = (45 ft3/min 3 3 3 <br /> ) (60 m.in/hour) •(0.0283168m /ft ) - 76.05 m /hour <br /> M /M )• Q • t = (0.03 kg/m3) •(76.05 m3/hour) • (8 hours) = 18.25 kg of gasoline <br /> f <br /> Converting kg of gasoline to pounds of gasoline yields: <br /> 18.25 kg of gas • 2.2046 lbs. of gas/kg of gas = 40 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields: ` <br /> 40 lbs. of gas • 0.16 gal of gas/lbs. of gas 6.439 gallons of gasoline <br /> r <br />
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