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EL DORADO
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2900 - Site Mitigation Program
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PR0505525
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Last modified
7/11/2019 10:04:27 PM
Creation date
7/11/2019 4:50:16 PM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
WORK PLANS
RECORD_ID
PR0505525
PE
2953
FACILITY_ID
FA0002387
FACILITY_NAME
KEYSTONE AUTOMOTIVE INDUSTRIES INC
STREET_NUMBER
632
Direction
S
STREET_NAME
EL DORADO
STREET_TYPE
ST
City
STOCKTON
Zip
95203
APN
14907033
CURRENT_STATUS
02
SITE_LOCATION
632 S EL DORADO ST
P_LOCATION
01
P_DISTRICT
001
QC Status
Approved
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EHD - Public
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act <br /> SIERRA LUMBER: Ground Water Pump Test Calculations <br /> Assumptions: <br /> A constant ground water pumping rate of 13.GPM <br /> • The effective porosity of soil at the site is 35% <br /> • The Jacobs Straight Line Method can:be utilized to calculate transmissivity (T) and <br /> storativity(S)utilizing draw-down versus time (minutes) on semi-logarithmic paper for each <br /> well location (Appendix J). <br /> Q = constant ground water pumping rate. <br /> As= draw-down per 1-logarithmic cycle. <br /> to W intercept of the straight line at the zero-time scale axis. <br /> r= radius from pumping well in feet. <br /> MW-1: Q = 13,GPM; As = 0.36 ft.; to= 1.3 minutes; r = 15 ft. <br /> T =264Q+As -4 264(13 GPM) -0.36 ft = 9,533 gpd/ft <br /> to, 1.3 minutes (1 hr/60min)(1 day/24hr) = 9.03 X:10-4 days, so <br /> -4 z_ <br /> S = 0.3 (T)(to) -r2 4 0.3 (9,533 d/ft)(9.03 x 10 days) -(15) - 0.011 <br /> ( )( o) gp <br /> MW-2: Q = 13 GPM; As = 0.82 ft.; to= 1.3 minutes; r= 10 ft. <br /> 4 T = 264Q-A s 264(13 GPM) -0.82 ft = 4,185 gpd/ft <br /> to= 1.3 minutes (l hr/60min)(l day/24hr) = 9.03 x 10-4 days, so <br /> S = 0.3 (T)(to) - r2 -+ 0.3 (5,720 gpd/ft)(9.03 x 10' days) (10)2 - 0.011 <br /> MW-4a: Q = 13 GPM; As = 0.74 ft.; t4= 1.3 minutes; r = 4 ft. <br /> T = 264Q-As 4 264(13 GPM) - 0.74 ft - 4,638 gpd/ft <br /> to- 1.3 minutes (1 hr/64min)(1 day/24hr) = 9.;03 x 10-4 days, so <br /> S - 0.3 (T)(to) - r24 0.3 (4,638 gpd/ft)(9.03 x 10'4 days) - (4)2- 0.079 <br /> EW-1: Q = 13 GPM; As = 9.6 ft.; to= 0.5 minutes; r= 0.5 ft. <br /> T = 264Q-0s -! 264(13 GPM) -9.6 ft = 357.5 gpd/ft <br /> to= 0.5 minutes (1 hr/64min)(1 day/24hr) = 3.47 x 10' days, so <br /> S = 0.3 (T)(to) - r2 -+ 0.3 (357.5 gpd/ft)(3.47 x 10-4 days) (0.5)2= 0.15 <br /> Advanced GeoEnviromnental.Inc- <br />
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