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I lie FORMER STOCKY ON PLATING FACILITY 632 South E1 Dorado Street, Stockton, California ' Assumptions ' 0 The distribution of dissolved hydrocarbon concentrations on the site can be approximated by an ellipse (See Figure 1), and ' 9 The effective porosity of soil at the site is estimated to be 30% • Data collected from the dune 2002 ground water sampling event are representative of ' existing site conditions The area of an ellipse can be calculated by the formula ' Ae = (long radius, a)(short radius, b)( 7854) For the estimated ellipse, a= 75 ft, b =45 ft, and thickness c =45 ft ' The average TP g H g concentration for the ellipse is estimated to be 66,785 micrograms per liter, thus ' concentration is equivalent to 0 00066785 grams per ml or 6 6 x 109 A mi is very nearly equivalent to a cubic centimeter of water, which by definition equals one gram, this concentration is nearly a umtless number ' The area of the ellipse is given by ' Ae = 75(45)(0 7854)=2650 fl The volume of the ellipse is given by ' Ve=Ae x c =2650 ftz x 45 ft = I 19,282 ft3 ' Water occupies the porosity in the soil,which is estimated to be 40%of the soil volume,so the total volume of water in the saturated portion of the ellipse is approximated by Ve =(0 40)(119,282 ft3) =47,712 ft3 One cubic foot of water contains 7 48 gallons, which weighs 8 337 lbs/gal, so the volume of the ' water in the ellipse is given by Ve = (47,712 ft)(7 48 gal/ft) = 356,891 gallons ' One gallon of water weighs 8 337 lbs/gal, so the mass of the water in the ellipse is given by Me= (356,891 gallons)(8 337 lb/gal) =2,975,400 lbs Multiplying Me by the hydrocarbon concentration yields the approximate mass of dissolved hydrocarbons in the saturated portion of the ellipse Meg= (2,975,400 lbs)(0 00066785) = 1,987 lbs gasoline