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• Because of the elevated concentrations of CO2 found in the <br /> influent ( . 75-1%) , this CO2 represents a significant amount of <br /> hydrocarbon removed On average in a hydrocarbon molecule there <br /> are 2 Hydrogens (H) for every Carbon (C) therefore each CO2 <br /> represents the oxidation of one CH2 radical This indicates that <br /> for ever mole of CO2 recovered one mole of CH2 has been <br /> destroyed. The molecular weight of CH2 is 14 gm/mole <br /> 14gm/435 6gm/lb= 0 032 lb/mole <br /> The volume of one mole of gas at STP = 22 4 1 <br /> 1 1 = . 0353 cf 22 41 x . 0353 cf/l = 0 79cf/mol <br /> Therefore one cf of pure CO2 represents <br /> 0 032 lb/mole / 0 . 79 cf/mole = 041 1b/cf of CH2 <br /> In gasses 10-. = 1/100 of a mole <br /> 041lb/cf/l00%= 00041 lb/cf/% <br /> The flow rated average of the CO2 content from the wells for the <br /> total flow from the vapor extraction system on 07/19/93 was <br /> 0 91% CO2 Normal air contains 0 0330-. CO2, the 0 877% in the <br /> sample zs most probably the result of oxidation of the <br /> hydrocarbons either chemical or biological At the current rate <br /> of vapor extraction, 82 36 cfm it can be calculated that the <br /> system is currently removing 42 6 pounds of hydrocarbon from the <br /> site per day as the result of biological or chemical degradation <br /> 82 . 36cfm x 0 877% x 0 . 00041lb/cfm/% x 1440min/day = 42 6 lb/day <br /> FLOW RATES <br /> Flow rates are measured at the site by use of orifice plates A <br /> one inch orifice is placed in lane for each well and two one inch <br /> orifices in parallel are used to measure the total flow. <br /> An orifice plate restricts the flow of air across it This <br /> restriction causes a pressure drop across the orifice By <br /> measuring the resulting pressure change across the orifice it is <br /> possible to calculate the air flow rate <br /> The flow rate is calculated by the pressure drop (millimeters <br /> (mm) water) across a square edge orifice plate <br /> Ve = CK sqr (P) Q = AVe <br /> Where : <br /> Ve= velocity in feet per minute (fpm) <br /> C = Orifice Coefficient = 0 65 (for orifice used) <br /> K = Constant = 794 6 mm water <br /> P = Pressure differential across the orifice <br /> Q = Flow rate in cubic feet per minute (CFM) <br /> A = Area orifice in square feet 1" = 0 00545 ft2 <br /> Q = A X 0 . 65 X 794 6 X sqr (P) <br /> page 4 of R604 , 07/09/93 <br /> y <br />