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lr - <br /> CALCULATIONS <br /> To calculate the pounds (lb) per day the concentration is <br /> multiplied by the, volume of air produced in one da <br /> The lab reports the Concentrations (C) of the air, ., sampling in <br /> ug/liter. The first step is to convert this valine to lbs/cf <br /> (pounds per cubic foot) . 28 , 321/cf <br /> 1 ug/l x 0 . 000001g/ug x 0 . 0022051g/g x <br /> 0 . 0000000621lb/cf.. <br /> The volume of air produced in - one day, equals the 'f-low rate (Q) x <br /> the time of flow.; <br /> V = Q x T = cf/day._ cf/min x 1440min/day <br /> The volume must be : corrected to standard temperature and <br /> pressure (STP) . <br /> P = Pressure = 14 . 7 lb/int @ STP <br /> V = Volume cf <br /> T = Temperature in degrees above absolute Zero = 491 . 58oR @ STP. <br /> I <br /> Using the Ideal Gas Law P1V1/T1 = P2V2/T2 <br /> Solving for V2 =PIV1T2/P2T1 <br /> 4 Assuming P1 = P2 = ' 14 . 7 lb/in2, P cancels from the equation <br /> leaving V2 = .V1T2/T1 . '. <br /> I V1 = Q cf/m x 1440 min/day <br /> T2 = 491 . 580R Tl = 459 . 58 + TOF at sight . <br /> V2 = Q cf/min x 1440 min/day x 491 . 580R/ (459 . 580 +` ,TOO) <br /> X lb/day C ug/l x 0 . 0000000621 lb 1/ug cf x Q cf/min x 1440 <br /> min/day x 491 . 580R/ (459 . 580 + TOF) <br /> Q for the Influent and Effluent samples = The well flow rate + <br /> the air flow. <br /> e I . <br /> f <br /> page 5 of R604 , 04/30/93 <br />