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ARCHIVED REPORTS XR0010896
EnvironmentalHealth
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EHD Program Facility Records by Street Name
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ELKHORN
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1050
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2900 - Site Mitigation Program
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PR0505234
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ARCHIVED REPORTS XR0010896
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Entry Properties
Last modified
8/1/2019 3:30:45 PM
Creation date
8/1/2019 2:37:01 PM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0010896
RECORD_ID
PR0505234
PE
2951
FACILITY_ID
FA0001103
FACILITY_NAME
Elkhorn Golf Club
STREET_NUMBER
1050
STREET_NAME
ELKHORN
STREET_TYPE
DR
City
STOCKTON
Zip
95209
CURRENT_STATUS
02
SITE_LOCATION
1050 ELKHORN DR
P_LOCATION
99
P_DISTRICT
003
QC Status
Approved
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EHD - Public
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Volume and Mass Calculation of Dissolved TPH-g <br /> Elkhorn Country Club <br /> -_� 1050 Elkhorn Drive, Stockton, California <br /> Assumptions: <br /> • The distribution of dissolved TPH-g concentrations on the site can be approximated by a cylinder <br /> with an average concentration of TPH-g; <br /> • The effective porosity of soil at the site is 35% (probably overestimated); and <br /> • Data collected from the Apnl 2001 ground water sampling event are representative of existing site <br /> conditions, <br /> _a The area of a cylinder can be calculated by the formula: <br /> Vc=rcrZh, where r is the radius of the cylinder and h is the height(equivalent to saturated <br /> zone within screened interval of the well). <br /> For the estimated cylinder,r= 15 ft,h= 10 ft <br /> - J <br /> The TPH-g concentration for the cylinder of ground water is estimated to be 570 micrograms per liter. This <br /> concentration is equivalent to 0.00057 g/l. <br /> I <br /> The area of the cylinder is given by: <br /> Vc —rcrzh -a 15 ft)' 10 ft =7,068 ft' <br /> Water occupies the porosity in the soil, which is estimated to be 35% of the soil volume, so the total volume <br /> of water in the saturated portion of the cylinder is approximated by: <br /> Vw=(0.35)(7,068 ft)=2,474 ft' <br /> 1 <br /> One cubic foot of water contains 7.48 gallons, so the volume of the water in the cylinder is given by: <br /> ( i <br /> Vw=(2,474 ft3)(7.48 gal/ft3) = 18,500 gallons <br /> One gallon of water equals 3.785 liter of water, so the volume of the water expressed as liters in the cylinder <br /> is given by: <br /> V= (18,500 gallons) (3.785 liter/gallon) =70,040 liter of water <br /> Volume to Mass Calculation of Dissolved TPH-g <br /> Multiplying the volume of water as liters by the TPH-g concentration(570 Mg/1)yields the approximate mass <br /> of TPH-g remaining at the site. <br /> MTP,-�=(70,040 liter of water) (0.00057 gll) =39.9 granas TPH-g or O.0.399 kg TPH-g <br /> Advanced GeoEnvironmenW,Inc. <br />
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