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ON SITE ANALYSIS <br /> During the two hour tests, a photoionizing detector (HNu PID <br /> w/10 2 ev bulb) and/or GasTech LEL/02 meter are used to perform <br /> constant exhaust monitoring, see Field Notes - Appendix A The <br /> LEL was used to insure that less than two pounds of hydrocarbons <br /> would be emitted during the test A commonly used LEL for <br /> gasoline is 1 401 = 14, 000 ppmv * mg/L/250 ppmv * 6 21X10-5 * flow <br /> rate (cfm) * 120 minutes = 1 04 lb at 5°s LEL and 2 08 lbs at 10% <br /> LEL The extraction well vacuum and flow is measured with a <br /> mercury manometer and the surrounding wells were gauged with a <br /> water manometer <br /> FLOW RATES <br /> Flow rates are measured at the site using an orifice plate . A one <br /> inch orifice-sampling manifold is placed directly on the casing <br /> of the monitor well , carefully avoiding any vacuum leaks . An <br /> orifice plate restricts the flow of air across it . This <br /> restriction causes a pressure drop across the orifice By <br /> measuring the resulting pressure change across the orifice it is <br /> possible to calculate the air flow rate The flow rate is <br /> calculated by the pressure drop (millimeters (mm) mercury or <br /> water) across a square edge orifice plate <br /> Ve = CK sgr (P) Q = AVe <br /> Where <br /> Ve= velocity in feet per minute (fpm) <br /> C = Orifice Coefficient = 0 65 (for orifice used) <br /> K = Constant = 794 6 for mm water or 2929 8 for mm <br /> mercury <br /> P = Pressure differential across the orifice <br /> Q = Flow rate in cubic feet per minute (CFM) <br /> A = Area orifice in square feet . 1" = 0 00545 ft2 <br /> Q = A X 0 . 65 X 794 6 X sqr (P) <br /> CALCULATIONS <br /> To calculate the pounds (lb) per day the concentration is <br /> multiplied by the volume of air produced in one day <br /> *The lab reports the Concentrations (C) of the air sampling in <br /> Ila l t'PY Th,= f-I rct ot-ep- I o tc .+r,r,t�cr s .� a_.. i L_ /_.t <br /> --,r• ----- •• — ••.•��.... r... -vtr �►+ acv �.vxxv tit V �.111.7 va.L l.ie l.V 11J.7/ 1.1 <br /> (pounds per cubic foot) lug/l x 0 . 000001g/ug x 0 00220Slb/g x <br /> 28 . 321/cf = 0 0000000621lb/cf <br /> The volume of air produced in one day, equals the flow rate (Q) x <br /> the time of flow <br /> V = Q x T = cf/day = cf/min x 1440min/day <br /> PAGE 4 R603 UPDATE-38 5/04/95 <br />