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Nitrate Mass Balance Calculation <br /> {Proposed Residence) <br /> data lriput: <br /> Effluent Quantity(Q): 560 galsrday <br /> Effluent Stream(NK): 35.00 mglL-N <br /> Site Area(A): 1.50 Acres <br /> Concentration Rain(Nb): 1.00 mglL-M <br /> Denitrification(d): 10.0% <br /> Deep Perc.of Rain(R):2.54 inn/yr <br /> Result: <br /> Mass Balance(k): 21.3 mgt-N <br /> MGL Drinking Water Nitrate as N: 10.0 MWL-W <br /> Petwlit of MCL Nitrate as N 213% <br /> Waste Loading(W): 5.02 LIE <br /> Equations: <br /> Find 1MY, <br /> (W) it = (Q) gal x. 1 W x. 36� x 1 acre x 12 in x 1 <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A)acre <br /> 5.02"r(site)=560 gairdayx(l-txs=R`/7.48 gats)x(365 days/f year)x(1 azo/43,560 sq tf)x(12 in f 1 ft)x(1 site f 1.5 acres) <br /> Ne= WN;(1A+RN <br /> W+R - Nantzsche-Fennemore Equation(Nc) <br /> 21.25 rrok-N=((5.02 Wyr x 35 mgt-N x(f-©:1))+(2.54 itW x 1 mg&-N)y(5.02"r+2:54 u'r/yr) <br /> Variables: <br /> Nc=Average'nitrate-N concentration(mg/1)of combined effluent and rainfall percolate(21.25 r n ig/L-N). <br /> W=Uniform waste water loading for study area(in/yr)(5.02 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(35 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil(10%). <br /> R Uniform deep percolation of rainfall(2.54 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 35 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 10%. <br /> 3. Estimated deep percolation of rainfall is 2.54 in/yr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is i mg/L-N. <br /> Irerracon <br />