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Nitrate Mass Balance Calculation <br /> (Existing and Proposed Residential Use) <br /> Data Input: <br /> Effluent Quantity(Q): 280 gaWday <br /> Effluent Stream(N„): 35.00 mg/L-N <br /> Site Area(Al: 1.00 Acres <br /> Concentration Rain(Nb): 1.00 mg/L-N <br /> Denitrification(d):T5.0% <br /> Deep Perc.of Rain(R): 5.76 in/yr <br /> Result: <br /> Mass Balance(N j: 11-0 mWL-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 110% <br /> Waste Loading(W): 3.76 kVyr <br /> Equations: <br /> Find <br /> (W) in = (Q) ggl x 1 ft3 x 365 day x 1 acre x 12 in x 1 <br /> yr day 7.48 gal 1 year 43,560 ft' 1 ft (A)acre <br /> 3.76 inyr(sde)=280 gayday x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre 143,560 sq-ft)x(12 in/1 R)x(1 ske/1 acres) <br /> N�= WNwt-d +RN_ <br /> W+R Hanhsche-Fennemore Ecuation(NO <br /> 10.98 mg/L-N=((3.76 kz/yr x 35 mg/L-N x(1-0.25))+(5.76 in/yr x 1mglL-N))/(3.76 inyr+5.76 imyr) <br /> Variables: <br /> Nc=Average nitrate-N concentration(mg/1)of combined effluent and rainfall percolate(10.98 mg/L-N). <br /> W=Uniform waste water loading for study area(intyr)(3.76 inchestyear). <br /> Nw=Total nitrate-N concentration of waste water percolate(35 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil(25%). <br /> R=Uniform deep percolation of rainfall(5.76 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 35 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 5.76 intyr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> lrerracon <br />