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Nitrate Mass Balance Calculatin, 42.39 acres <br /> Fit,' Data Input: <br /> Effluent Quantity(Q): 678 gals/day Concentration Rain (Ne): 1.00 mg/L-N <br /> Effluent Stream (NN,): 51.60 mg/L-N Denitrification (d): 25.0% <br /> Site Area (A): 42.39 Acres Deep Perc. of Rain (R): 2.52 in/yr <br /> Waste Loading (W): 0.22 in/yr <br /> Result: <br /> Mass Balance(Nj: 4.0 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N i <br /> Percent of MCL Nitrate as N 40% <br /> 1 <br /> Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find W j <br /> !M_ yr day 7.48 gal 1 year 43,560 ft' 1 ft (A)acre <br /> 0.22 in/yr(site)=678 ga%dayx(1 cu-ft/7.48 gals)x(365 days/i year)x(1 acre/43,560 sq-ft)x(12 in/1 It)x(1 site/42.39 acres) x <br /> i� N�= WN-0-d)+RN,, HanLsche-FennemoreEquation L c) ' <br /> W+R <br /> t <br /> 3.96 mg/L-N=((0.22 in/yr x 51.6 mg/L-N x(1-0.25))+(2.52 in/yr x 1mg/L-N))/(0.22 in/yr+2.52 in/yr) <br /> I <br /> Variables: <br /> Nc= Average nitrate-N concentration (mg/1)of combined effluent and rainfall percolate(3.96 mg/L-N). <br /> i W = Uniform waste water loading for study area (in/yr) (0.22 inches/year). <br /> - Nw =Total nitrate-N concentration of waste water percolate(51.6 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil (25%). <br /> R= Uniform deep percolation of rainfall (2.52 in/yr). <br /> Nb = Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 51.6 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 2.52 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> F4' <br /> i <br /> F 1 <br /> J1 <br /> I <br /> I ! <br /> 6 � <br /> Fil ' <br /> NEIL O. ANDERSON <br /> AN D ASSOCIATES <br /> Plate 7 <br /> i <br /> I <br />