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Nitrate Mass Balance Calculation <br /> I <br /> Data Input: <br /> Effluent Quantity(Q): 280 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream(NH,): 40.00 mg/L-N Denitrification (d): 25.0% <br /> Site Area (A): 2.05 Acres Deep Perc. of Rain (R): 1.27 in/yr <br /> Result: <br /> Mass Balance(N,):-18.1 mg/L-N-- ---•� <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N Waste Loading (W): 1.84 in/yr <br /> Percent of MCL Nitrate as N 181% <br /> li <br /> Equations: <br /> Ir (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ftz 1 ft (A)acre <br /> 1.84 in/yr(site) =280 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/2.05 acres) <br /> N,= WN,..(1-d)+RN, Hantzsche-Fennemore E uation Nc <br /> W+R <br /> 18.14 mg/L-N=((1.84 in/yr x 40 mg/L-N x(1-0.25))+(1.27 in/yr x 1mg/L-N))/(1.84 in/yr+1.27 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration (mg/1)of combined effluent and rainfall percolate(18.14 mg/L-N). <br /> W=Uniform waste water loading for study area(in/yr) (1.84 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(40 mg/L-N). <br /> d= Fraction of nitrate-N loss due to denitrification in the soil (25%). <br /> t R=Uniform deep percolation of rainfall (1.27 in/yr). <br /> Nb= Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 40 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25°1x. <br /> 3. Estimated deep percolation of rainfall is 1.27 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> 1 <br /> i - <br /> it <br /> I I <br /> Y i <br /> NEIL O. ANDERSON <br /> A N D A S S O C I A T E S <br /> Plate 7 <br /> i <br />