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Nitrate Mass Balance Calculation <br /> Parcel 2 <br /> i <br /> Data Input: <br /> Concentration Rain N 1.00 m 2-N <br /> Effluent Quantity(Q): 350 gals/day ( �) g <br /> Effluent Stream (N,)' 45.00 mg/L-N Denitrification (d): 35.0% <br /> 4 Site Area (A): 2.08 Acres Deep Pere. of Rain (R): 6.00 in/yr <br /> Result: ' <br /> Mass Balance(N.): 8.7 mg/L-N Waste Loading(W): 2.26 inlyr <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> }, Percent of MCL Nitrate as N 87% <br /> Equations: <br /> in = Q al x 1 ft 3 x 365 da Y x 1 acre x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A) acre <br /> 2.26 in/yr(site) =350 gal%day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/2.08 acres) <br /> i <br /> N,= WN 1-d +RN Hantzsche-Fennemore Equation Nc <br /> W+R <br /> F" 8.73 mg/L-N= ((2.26 in/yr x 45 mg/L-N x (1-0.35))+(6 in/yr x 1mg/L-N))/(2.26 in/yr+6 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration (mg/1) of combined effluent and rainfall percolate(8.73 mg/L-N). <br /> W= Uniform waste water loading for study area(in/yr) (2.26 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate (45 mg/L-N). <br /> d=Fraction of nitrate-N'loss due to denitrification in the soil (35%). <br /> R=Uniform deep percolation of rainfall (6 in/yr). <br /> a <br /> i <br /> Assumptions: <br /> k 1. Total nitrogen concentration of waste stream based on estimate of 45 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 6 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> 1~ <br /> NEIL O. ANDERSON <br /> AN D ASSOCIATES <br /> . f <br /> �t <br />