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I Nitrate Mass Balance Calculation <br /> Parcel 4 <br /> I� a: <br /> i <br /> I <br /> Data Input: <br /> Effluent Quantity(Q): 280 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream (NH,): 45.00 mg/L-N Denitrification(d): 35.0% <br /> Site Area(A): 2.96 Acres Deep Perc. of Rain (R): 6.00 in/yr <br /> ii <br /> i— Result: <br /> Mass Balanee(N.): 5.9 mg/L-N Waste Loading (W): 1.27 in/yr <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 59% <br /> Equations: <br /> € {W} in = (Q) gal x <br /> _1 2 x 365 day x 1 acre x 12 in x 1 Find <br /> ,i yr day 'i 7.48 gal 1 year 43,560 ft' 1 ft (A)acre <br /> 1.27 in/yr(site) =280 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x (1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/2.96 acres) <br /> 4 F <br /> Nc= WN (1 d)+RNA Nantzsche-Fennemore E uation Nc <br /> W+R <br /> 5.94 mg/L-N=((1.27 in/yr x 45 mg/L-N x(1-0.35))•+(6 in/yr x 1mg/L-N))/(1.27 in/yr+6 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration (mgll)of combined effluent and rainfall percolate(5.94 mg1L-N). <br /> Ii W= Uniform waste water loading for study area(in/yr) (1.27 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate (45 mg/L-N). <br /> d= Fraction of nitrate-N'loss due to denitrification in the soil (35%). <br /> r R=Uniform deep percolation of rainfall (6 intyr). <br /> i <br /> 0 <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 45 mg/L-N. <br /> -{ 2. Fraction of nitrate-N,loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 6 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> L <br /> FF , <br /> NEIL O. ANDERSON <br /> AN D ASSOCIATES <br /> F <br /> =e <br />