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-Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 252 gals/day(?, Z7 Concentration Rain (Nb): 1.00 mg/L-N <br /> z Effluent Stream (N,,): 45.00 mg/L-N0-Zz o Denitrification (d): 25.0% <br /> + Site Area(A): 1.12 Acres Deep Perc. of Rain (R): 2.52 in/yr <br /> Waste Loading (W): 3.02 in/yr <br /> s Result: <br /> Mass Balance(N,): 18.9 mg/L-N <br /> a MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 18911% <br /> j Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A)acre <br /> 3.02 in/yr(site) =252gal/day x (1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/1.12 acres) <br /> j Nr= WN,.,(1-d)+RN,, Hantzsche-Fennemore Equation(Nc) <br /> W+R <br /> 18.87 m <br /> jN- 02 in yr x 5 mg/L-N x (1-0.25))+(2.52 in/yr x 1mg/L-N))/3.02 lyr+2.52 in/yr) <br /> `Variables: <br /> Nc=Average nitrate-N concentration (mgll)of combined effluent and rainfall percolate(18.87 mg/L-N). <br /> W=Uniform waste water loading for study area(in/yr) (3.02 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate (45 mg/L-N). <br /> d= Fraction of nitrate-N loss due to denitrification in the soil(25%). <br /> R=Uniform deep percolation of rainfall (2.52 in/yr). <br /> Nb= Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> �i 1. Total nitrogen concentration of waste stream based on estimate of 45 mg/L-N. <br /> 1 _! 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 2.52 in/yr, see deep percolation of rain worksheet. <br /> Fi <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> /�J Ad <br /> Fil <br /> NEIL O. ANDERSON <br /> A N D A S S O C I A T E S <br /> Plate 5 <br />