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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 420 gals/day <br /> Effluent Stream(N,): 35.00 mgA-N <br /> Site Area(A): 0.78 Acres <br /> Concentration Rain(Ne): 1.00 mg/L-N <br /> Denitrification(d): 35.0% <br /> Deep Parc.of Rain(R): 2.27 in/yr <br /> Result: <br /> Mass Balance(Nj: 17.6 mg/L-N <br /> MCL Drinking Water Nitrate as M. 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 176% <br /> Waste Loading(W): 7.24 inyr <br /> Equations: <br /> Find <br /> (W) to- = (Q) Q1 x 1$ x 365 day x 1 acre x ]2jp- x 1 <br /> yr day 7.48 gal 1 year 43,%0 ft2 1 ft (A)acre <br /> 7.24 ii/yr(site)=420 gakday x(1 cu-ft/7.46 gals)x(365 daysr 1 year)x(1 acre 143,560 sq-ft)x(12 in/1 ft)x(1 site/0.78 acres) <br /> N,= WNJ I-dI+RNQ <br /> W+R Hanlzsche-Fennemore Equation(Nc) <br /> 17.56 mg1L-N=((7.24 inyr x 35 mg4.-N x(1-0.35))+(2.27 myr x lmgrL-N))1(7.24 inyr+2.27 in7yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration(mg/I)of combined effluent and rainfall percolate(17.56 mg/L-N). <br /> W=Uniform waste water loading for study area(m/yr)(724 inches/year). <br /> Nw=Total nilrate-N concentration of waste water percolate(35 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denittfication in the soil(35%). <br /> R=Uniform deep percolation of rainfall(2.27 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/04). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 35 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 2.27 intyr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> lrerracon <br />