Laserfiche WebLink
Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 3,045 gals/day Concentration Rain(Nb): 1.00 mg/L-N <br /> Effluent Stream(Nv,): 62.00 mg/L-N Denitrification(d): 35.0916 <br /> Site Area(A): 17.10Acres Deep Perc.of Rain(R): 5.76 in/yr <br /> Result: Waste Loading(W): 2.39 in/yr <br /> Mass Balance(NS): 12.5 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 125% <br /> Equations: <br /> i� <br /> (W) in = (Q) gal x 1 1113 x 365 day x 1 acre x 12 in x i Find W <br /> yr day 7.48 gal 1 year 43,560 ftz 1 ft (A)acre <br /> 2.39 in/yr(site)=3,045 ga!/day x(1 cu-ft/7.48 gals)x(365 days/i year)x(1 acre/43,560 sq-ft)x(12 in/1 R)x(1 site/17.1 acres; <br /> f <br /> I <br /> N�= WN 1-d+RN <br /> W+R Han sche-Fennemore Equation(Nc) <br /> -7 <br /> 12.54 mg/L-N=((2.39 in/yr x 62 mg/L-N x(1-0.35))+(5.76 in/yr x Img/L-N))/(2.39 in/yr+5.76 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration(mg/1)of combined effluent and rainfall percolate(12.54 mg/L-N). ` <br /> W=Uniform waste water loading for study area(in/yr)(2.39 inches/year). I <br /> Nw=Total nitrate-N concentration of waste water percolate(62 mg/L-N). <br /> d= Fraction of nitrate-N loss due to denitrification in the soil(35%). <br /> R=Uniform deep percolation of rainfall(5.76 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 62 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 5.76 in/yr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N, <br /> NEIL O. ANDERSON <br /> AN D ASSOCIATES <br /> Plate 2 <br />