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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q):1i 12 gals1day Concentrahon Rain(Nb): 1.00 mg/L-N <br /> Effluent Stream(Nwj:185.00 N I Denitrification(d): 35.0% <br /> Site Area(A):17.79 Acres I Deep Pere.of Rain(R):JZ52inlyr <br /> Result: <br /> Maas Balance(N j: 4.9 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N Waste Loading (W): 0.19 in/yr <br /> Percent of MCL Nitrate as N 49% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft" x 385 day xe x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 If 1 It (A)acre <br /> 0.19 in/yr(site)=112 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/7.79 acres) <br /> N,= WN-(1il)+RN.. HantrscherFe0nemote F-gLtl On fNc1 <br /> W+R <br /> 4.86 mg/L-N= ((0.19 in/yr x 85 mg/L-N x(1-0.35))+(2.52 In/yr x 1 mg/L-N))I(O.f 9 in/yr+2.52 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration(mg/1)of combined effluent and rainfall percolate(4.86 mg/L-N). <br /> W=Uniform waste water loading for study area(intyr)(0.19 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(85 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil(35%). <br /> R=Uniform deep percolation of rainfall(2.52 inlyr). <br /> Nb=Background nftrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 85 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denftrlfication in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall Is 2.52 intyr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> �I NEILO. ANDERSON <br /> /alar A N D A S S b C I A T H 5 <br /> Plate 6 <br />