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Nitrate Mass Balance Calculation <br /> Lot 31 <br /> Data Input: <br /> - Effluent Quantity(Q): 560 galsiday Concentration Rain(Nb): 1.00 mg/L-N <br /> Effluent Stream(NV,): 35.00 mg/L-N Denitrification(d): 25.0% <br /> Site Area(A): 9.82 Acres Deep Perc.of Rain(R): 3.38 in/yr <br /> Waste Loading(W): 0.77 in/yr <br /> Result: <br /> Mass Balance(N,): 5.7 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N: 57% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find W <br /> yr day 7.48 gal 1 year 43,560 ft' 1 ft (A)acre <br /> 0.77 in/yr(site) =560 gal/day x(1 cu-ft/7.48 gals)x(365 daysi 1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/9.82 acres) <br /> N�= WNJ1-d)+RN„ Hantzsche-Fennemore EOuation(Nc) <br /> W+R <br /> 5.67 mg/L-N=((0.77 in/yr x 35 mg/L-N x(1-0.25))+(3.38 in/yr x 1mg/L-N))/(0.77 in/yr+3.38 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration(mg/1)of combined effluent and rainfall percolate(5.67 mg/L-N). <br /> W=Uniform waste water loading for study area(in/yr)(0.77 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(35 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil(25%). <br /> R=Uniform deep percolation of rainfall(3.38 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 35 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 3.38 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> '44 NEIL O. ANDERSON <br /> A N D A S S O C I A T E S <br /> Plate 9 <br />