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Mass balance calculations for TPHg in groundwater <br /> (413)*(31416) r1 r2 * r3 <br /> volume of impacted <br /> groundwater(elipsoid)= 41888 * 13 13 * 7 25 <br /> Volume of impacted <br /> groundwater= 5,132 ft3 <br /> Average concentration of <br /> contaminant in groundwater <br /> 1,637 pg/L <br /> Chemical TPH-g <br /> mass = 5,132 ft3 * 2832 L * 03 * 1,637 Vg/ 0000000001 kg <br /> ft3 L pg/L <br /> mass = 0 071 kg <br /> mass = 0 157 lbs <br /> r1 and r2 denote one half the width of contaminant zone (26 ft), r3 denotes one half of the thickness(gwt to bottom of <br /> screen=14 5ft) <br /> Average concentration equals the mean concentration of TPHg in SB1, S62, and MW1 <br /> Assume 30% porosity <br />