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FF) <br /> p-out Interval Equation: / <br /> DF)x 1.5=5,775 gals ✓ <br /> uted Tank Capacity=2,575+5,775 =2=4,175 galsComputation• <br /> 3.500 gal total tank capacity based on min detention time x 070(30%volume lost to stud _/scum accumulation) <br /> 1,375 gpd ADF x 1.5 (Peaking Factor) <br /> Detention Time= 1.2 days. Therefore a 3,500 allon septic tank is suitable for sufficient detention time <br /> for the Dry Goods Building. <br /> GUARD/SCALE HOUSE BUILDINGS AND OFFICE TRAILERS <br /> These buildings should have an ADP of no more than 100 gallons per day. Therefore, a Base Tank <br /> Capacity of using a 1,200 gallon septic tank should be sufficient. <br /> LARGE CENTRAL RECEIVING SEPTIC TANK <br /> The size of the large central receiving septic tank can be determined from the total of the ADP's <br /> from each location, and the total of each septic tank volume,also from the four locations. These <br /> two quantities are then plugged into the Detention Time Equation to check for adequate large tank <br /> size: <br /> Avc)-aze Daily Flows <br /> Crush Office =918 gpd <br /> Dry Goods = 1,375 gpd <br /> Guard/Scale = 100 gpd <br /> Office Trailers= 100 apd <br /> TOTAL =2,493 gpd <br /> Septic Tank Sizes <br /> Crush Office =2,500 gals <br /> Dry Goods =3,500 gals <br /> Guard/Scale = 1,200 gals <br /> Office Trailers= 1.200 gals <br /> TOTAL = 8,400 gals <br /> Detention Time Computation: <br /> 8.000 gal total tank capacity based on min.detention time x 0.70(30%volume lost to stud elscum accumulation) <br /> 21500 gpd ADP 71.5 (Peaking Factor) <br /> Detention Time= 1.5 days. Therefore, n 8,000 all t is theoretically suitable for sufficient <br /> detention time for the total anticipated in nt'Flo A 9,006 Ilon tank would give a detention time of <br /> 1.7 days. <br /> Page5 of 7 <br /> Chesney Consulting /� <br />