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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 560 gals7day Concentration Rain (Nn): 1.00 mgt-N <br /> Effluent Stream(N,,.): 45,00 mg/L-N Denitrification (d); 25.0% <br /> Site Area(A): 5.00 Acres Deep Perc. of Rain(R): 5.76 in/yr <br /> Waste Loading(W): 1.51 in/yr <br /> Result <br /> Mass Balance(N j: 7.8 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 78% <br /> Equations: <br /> (W) ir- = (Q) gal x lit' x 365 day x 1 acre x 12 In x 1 Find <br /> yr day 7.45 gal 1 year 43,560 ft' 1 ft (A)acre <br /> 1.51 irr/yr(site) =560 gal/day x(1 cu-ft/7.48 gals)x(365 days/l year)x(1 acre/43.560 sq-R)x(12 011 R)x(1 sift 15 acres) <br /> N,= WN,,,(1-d)*RNA Hantzsche-Fennemore Fouation (NC) <br /> W+R <br /> 7.79 mgt-N-((1.51 in/yr x 45 mg/L-N x(1-0.25))+(5.76 in/yr x 1mg/L-N))1(1.51 in/yr+5.76 in/yr) <br /> Variables: <br /> No=Average nitrate-N concentration(mg/1)of combined effluent and rainfall percolate(7 79 mg/L-N). <br /> W= Uniform waste water loading for study area(in/yr)(1.51 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(45 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil (25%). <br /> R= Uniform deep percolation of rainfall (5.76 infyr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 45 mgtL-N. <br /> 2, Fraction of nitrate-N loss due to denitrification In the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 5.76 in/yr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall Is 1 mg/L-N. <br /> �I NEIL O. ANDERSON <br /> ,.46 A N D A 5 5 O C I A T E 5 <br /> Plate 10 <br />