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"Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 382 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream (Nj: 45.00 mg/L-N Denitrification (d): 25.0% <br /> Site Area(A)—4.84 Acres-- Deep Perc.of Rain (R): 6.84 in/yr <br /> Waste Loading (W): 1.06 in/yr <br /> Result: U s <br /> Mass Balance (Nj! &4 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N DO <br /> Percent of MCL Nitrate as N 54% <br /> Equations: ��r <br /> Find � 5 2 —Id <br /> (tM in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 \c�lG,( <br /> yr day 7.48 gal 1 year 43,560 ft` 1 ft (A) acre <br /> 1.06 in/yr(site) =382 gal/day x (1 cu-ft/7.48 gals)x(355 days)1 year) x (1 acre/43.560 sq-R)x (12 in/1 ft)x (1 site/4.84 acres) <br /> .-_N, WN (1-d)+RN„ Hantzsche-Fennemore EQuation(Ncl <br /> W+R _l-o Y' <br /> 5.4 mg/L-N=((1.06 in/yr x 45 mg/L-N z (1-0.25))+(6.84 in/yr x 1mg/L-N))/(1.06 in/yr+6.84 in/yr) /(1 <br /> Variables: <br /> Nc=Average nitrate-N concentration(mg/1) of combined effluent and rainfall percolate (5.4 mg/L-N). <br /> W= Uniform waste water loading for study area (in/yr) (1.06 inches/year). L <br /> Nw=Total nitrate-N concentration of waste water percolate(45 mg/L-N). n \C <br /> d = Fraction of nitrate-N loss due to denitrification in the soil (25%). <br /> R = Uniform deep percolation of rainfall (6.84 in/yr). <br /> Nb = Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1_ Total nitrogen concentration of waste stream based on estimate of 45 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 6.84 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. ) <br /> _ �o <br /> NEIL O. ANDERSON <br /> AND ASSOC I A T E S <br /> Plate 10 <br />