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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q):1788 gals/day Concentration Rain(N°): 1.00 mg/L-N <br /> Effluent Stream(N„): 50.00 mg/L-N Denitrification(d): 25.0% j <br /> Site Area (A): 22.80 Acres Deep Pere.of Rain(R): 5.31 inlyr <br /> Result: . <br /> Mass Balance(N°): 3.9 mg/L-N <br /> Ir MCL Dri 1 ( ter Nitrate as N: 10.0 m WBsteLoading (N): 0.46 in/yr <br /> Percent of MCL Nitrate as N 39% <br /> V Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 1,1 Find <br /> ` yr day 7.48 gal 1 year 43,560 ft' 1 ft (A)acre <br /> 0.46 in/yr(site) =788 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre 143,560 sq-ft)x(12 in/1 ft)x(1 site/22.8 acres) <br /> N°= WN...(1-d)+RN„ Hantzsche-Fenn more aron <br /> - .. W>�- -r <br /> 3.94 mg/L-N=((0.46 in/yr x 50 mg/L-N x(1-0.25))+(5.31 in/yr x 1mg/L-N))/(0.46 in/yr+5.31 in/yr) c 90 j�Js" <br /> Varia'blm <br /> Nc=Average nitrate-N concentration (mg/I)of combined effluent and rainfall percolate(3.9�). <br /> W= Uniform waste water loading for study area (in/yr) (0.46inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(50 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil(25%). <br /> R=Uniform deep percolation of rainfall (5.31 in/yr). <br /> Nb=Background nitrate-N concentration of (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 50 mg/L-N. <br /> — 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed1TE5%. <br /> 3. Estimated deep percolation of rainfall is 5.31 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> — <br /> NEIL O. ANDERSON <br /> AN D ASSOCIATES <br /> Plate 3 <br /> — <br />