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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 370 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream (N.): 49.80 mg/L-N <br /> Site Area(A): 14.43Acres Denitrification (d): 25.0% <br /> Deep Perc. of Rain (R): 5.76 in/yr <br /> Result: , Waste Loading (W): 0.34 in/yr <br /> Mass Balan NJ: 3.1 mg/L N <br /> MCL Drinking Water Nitrate as <br /> Percent of MCL Nitrate as N 31% <br /> Equations: <br /> (W) in _ (Q) 9®1 x 1ft3 x 365 day x 1 a re x 12 in x 1 Find W <br /> yr day 7.48 gal 1 year 433 560 ft' 1 ft (A)acre <br /> 0.34 in/yr(sfe)=370 gal/day x(1 cu-R/7.48 gals)x(365 days/1 year)x(1 acre/43,560 <br /> Sq-&)x(12 in/1 R)x(1 slte/14.43 acres) <br /> N�= WN_Lt-d)+RN n che-Fennemor E u <br /> 305 mg/L-N=((0.34 in/yr x 49.8 mg/L N x(10 25))+(5.761n/yr xInrQ/L-N))/(0.341n/yr+5.761n/yr)— 30O <br /> a <br /> Variables: 1-76 / G/ <br /> Nc = Average nitrate-N concentration (mg/1)of combined effluent and rainfall percolate(3.05 mg/L-N). <br /> W= Uniform waste water loading for study area (in/yr) (0.34 inches/year). <br /> Nw =Total nitrate-N concentration of waste water percolate(49.8 mg/L-N). <br /> d = Fraction of nitrate-N loss due to denitrification in the soil(25%). <br /> R = Uniform deep percolation of rainfall(5.76 in/yr). <br /> Nb = Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 49.8 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 25%. <br /> 3. Estimated deep percolation of rainfall is 5.76 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/1--N. <br /> NEIL O. ANDERSON <br /> A N D A 5 5 0 C I A T E 5 <br /> Plate 7 <br />