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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q : 378 gals/day Concentration Rain(Nb): 1.00 mg/L-N <br /> Effluent Stream (N,): 85.00 mg/L-N Denitrification(d): 15.0% <br /> Site Area(A): 77.56 Acres Deep Parc.of Rain(R): 3.54 inlyr <br /> Result: <br /> Mass Balance(N j: 2.3 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N Waste Loading(W): 0.07 in/yr <br /> Percent of MCL Nitrate as N 23% <br /> Equations: <br /> (W) in = (Q) gal x 1 W x 365 day x 1 acre x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ftz 1 ft (A) acre <br /> 0.07 in/yr(site) =378 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre 143,560 sq-ft)x(12 in/1 R)x(1 site 177.56 acres) <br /> N�= WN 1-d( 1+RNe Hantzsche-Fennemore Equation(No) <br /> W+R <br /> 2.29 mg/L-N=((0.07 in/yr x 85 mg/L-N x(1-0.15))+(3.54 in/yr x 1mg/L-N))/(0.07 in/yr+3.54 in/yr) <br /> Variables: \, <br /> Nc=Average nitrate-N concentration(mg/1)of combined effluent and rainfall percolate(2.29 mg/L-N). <br /> W=Uniform waste water loading for study area(in/yr)(0.07 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(85 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the soil(15%). <br /> R=Uniform deep percolation of rainfall(3.54 in/yr). <br /> Nb= Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 85 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to dendrification in the soil is assumed to be 15%. <br /> 3. Estimated deep percolation of rainfall is 3.54 in/yr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> lrerracon <br />