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Nitrate Mass Balance Calculation <br /> F1 r <br /> E <br /> F! Data Input: <br /> Effluent Quantity(Q): 104 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream (N,,): 85.00 mg/L-N Denitrification (d): 35.0% <br /> Site Area(A): 12.31 Acres Deep Perc. of Rain (R): 4.67 i2/ r <br /> Result: <br /> Mass Balance(N.): 2.3 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N Waste Loading (W): 0.11 in/yr <br /> G Percent of MCL Nitrate as N 23% <br /> i <br /> 3 Equations: <br /> f (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find <br /> E = 0.//3S,g89 <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A)acre <br /> 17.I 990 doDO ZZ' Q.6g 123oF� <br /> 0.11 in/yr(site) =104 ga!/day x(1 cu-ff7 7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/12.31 acres) <br /> "//3" <br /> N�= WN,,,i1-dib Hanizsche-Fennemore Equation(NO <br /> II �1 — <br /> W+R <br /> 2.29 mg/L-N=((0.11 in/yr x 8 mg/L-N x(1-0.35))+(4.67 in/yr x 1 mg/L-N))/(0.11 in/yr+4.67 in/yr) 2 2 <br /> Z-7S <br /> Variables: <br /> Nc=Average nitrate-N concentration (mg/1)of combined effluent and rainfall percolate(2.29 mg/L-N). <br /> E W= Uniform waste water loading for study area(in/yr) (0.11 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(85 mg/L-N). <br /> d= Fraction of nitrate-N loss due to denitrification in the soil (35%). <br /> R=Uniform deep percolation of rainfall (4.67 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br />` 1. Total nitrogen concentration of waste stream based on estimate of 85 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 4.67 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> I <br /> 4 <br /> �t <br /> F+ <br /> NEIL O. ANDERSON <br /> AND ASSOC I A T E S <br /> Plate 1 <br /> F1° <br />