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Ft <br /> Nitrate Mass Balance Calculation <br /> Data Input: <br /> �^ Effluent Quantity(Q): 1,039 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> { Effluent Stream (N,,,): 63.48 mg1L-N Denitrification(d): 35.0% <br /> r - Site Area(A): 20.43 Acres Deep Perc.of Rain (R): 5.76 in/yr <br /> Result: <br /> F Mass Balance(N.): 5.3 mg/L-N <br /> L <br /> r MCL Drinking Water Nitrate as N: 10.0mg/L-N Waste Loading (W): 0.68 inlyr <br /> rPercent of MCL Nitrate as N 53% <br /> Equations: <br /> (W) in = (Q) gal x 1 ft3 x 365 day x 1 acre x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ftZ 1 ft (A)acre <br /> 0.68 in/yr(site) =1,039 gal/day x (1 cu-ft/7.48 gals)x(365 daysl 1 year)x(1 acre/43,560 sq-ft)x(12 in/1 ft)x(1 site/20.43 acres) <br /> Hantzsche-Fennemore Equation(Nc� <br /> W+R <br /> 5.27 mg/L-N= ((0.68 inlyr 63.48 mglL-N x (1-0.35))+(5.76 in/yr x 1 mg/L-N))1(0.68 inlyr+5.76 inlyr) S Z <br /> Variables: <br /> Nd=Average nitrate-N concentration (mg/l)of combined effluent and rainfall percolate(5.27 mg/L-N). <br /> W= Uniform waste water loading for study area (inlyr) (0.68 inches/year). <br /> NW=Total nitrate-N concentration of waste water percolate (63.48 mg/L-N). <br /> d= Fraction of nitrate-N loss due to denitrification in the soil (35%). <br /> R= Uniform deep percolation of rainfall (5.76 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 63.48 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 5.76 inlyr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br />{ <br /> F <br /> i r'! <br /> �i <br /> k _1 <br /> NEIL O. ANDERSON <br /> 1711. AND ASSOC I A T E S <br /> Plate 10 <br /> r <br />