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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q : 548 gals/day Concentration Rain (Nb): 1.00 mg/L-N <br /> Effluent Stream(NW): 47.60 mg/L-N Denitrification (d): 20.0% <br /> Site Area-W:-45.00 Acres Deep Perc. of Rain (R): 1.27 in/yr <br /> Result: <br /> Mass Balance(Nj: 5.2 mg/L-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N Waste Loading (W): 0.16 in/yr <br /> Percent of MCL Nitrate as N 52% <br /> Equations: <br /> (W) in = (Q) gal x 1 f't� x 365 day x 1 afire x 12 in x 1 Find <br /> yr day 7.48 gal 1 year 43,560 ft2 1 ft (A)acre <br /> 0.16 in/yr(site) =548 gal/day x (1 cu-ft/7.48 gals)x (365 days/1 year)x (1 acre/43,560 sq-ft)x (12 in/1 ft)x (1 site/45 acres) <br /> N,= WN,.,(1-d)+RN,, Hantzsche-Fennemore Equation(NO <br /> W+R <br /> 5.23 mg/L-N= ((0.16 in/yr x 47.6 mg/L-N x(1-0.2))+(1.27 in/yr x 1 mg/L-N))/(0.16 in/yr+1.27 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration (mg/1) of combined effluent and rainfall percolate(5.23 mg/L-N). <br /> W= Uniform waste water loading for study area (in/yr) (0.16 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(47.6 mg/L-N). <br /> d= Fraction of nitrate-N loss due to denitrification in the soil (20%). <br /> R= Uniform deep percolation of rainfall (1.27 in/yr). <br /> Nb= Background nitrate-N concentration of rainfall (1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 47.6 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 20%. <br /> 3. Estimated deep percolation of rainfall is 1.27 in/yr, see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> NEIL O. ANDERSON <br /> AN D ASSOCIATES <br /> Plate 6 <br />