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Nitrate Mass Balance Calculation <br /> Data Input: <br /> Effluent Quantity(Q): 850 gals/day Concentration Rain(Nb): 1.00 mg&-N <br /> Effluent Stream(N,):159.82 mgt N Denitrification(d): 30.0% <br /> Site Area(A):15.00 Acres Deep Pere.of Rain I 5.76 in/r <br /> Result: <br /> Mass Balance(N,): 12.6 m_q&-N <br /> MCL Drinking Water Nitrate as N: 10.0 mgt-N Waste Loading(W): 2.29 inyr <br /> Percent of MCL Nitrate as N 126% <br /> Equations: <br /> (W) in = (Q) gal x 1 W x 365 day x 1 acre x 12 in x 1 Find <br /> yr day 7.46 gal 1 year 43,560 ftz f ft (A) acre <br /> 2.29 in/yr(site) =850 gal/day x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre/43,560 sq-1t)x(12 in/1 It)x(1 site/5 acres) <br /> N,= WN�„(1-d)+RN- Hanfzsche-Fennemore Ecuation We) <br /> W+R <br /> 12.61 mg/L-N=((2.29 i*r x 59.82 mgrL-N x(1-0.3))+(5.761nlyr x 1mg1L-N))/(2.29 fn/yr+5.76 inyr) <br /> Variables: <br /> No=Average nitrate-N concentration(mgJl)of combined effluent and rainfall percolate(12.61 mg/L-N). <br /> W=Uniform waste water loading for study area(intyr)(2.29 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(59.82 mg/L-N). <br /> d=Fraction of nitrate-N loss due to denitrificatlon in the soil(30%). <br /> R=Uniform deep percolation of rainfall(5.76 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 59.82 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the soil is assumed to be 30%. <br /> 3. Estimated deep percolation of rainfall is 5.76 intyr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> NEIL O. ANDERSON <br /> AND�44 ASSOCIATES <br /> Plate 2 <br />