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MASS CALCULATION: <br /> VOLUME OF EXTRACTED HYDROCARBONS (Gasolene) <br /> Art& Artists <br />' 204 East Lodi Avenue, Lode, California <br /> The hydrocarbon mass removed during the operating period can be calculated using the following <br /> equation M= C•Q•t <br /> where M= cumulative mass recovered (kg) <br /> ' C = vapor concentration (kg/m3) <br /> Q = extraction flow rate (m3/hr) <br /> t= operational period <br /> 31 July to 29 August 1996 <br /> ' using C = 765 µg11 =0 000765 kg/m3 <br /> Q = 70 cfm = 1189m3/hr <br /> ' t= 5766hr <br /> 0 000765 • 118 9 . 576 6 = 52 4 kg of gasoline <br /> ' 52 4 kg • 2 2046 lbs/kg = 116 lbs of gasoline <br /> to convert lbs of gasoline to gallons of gasoline, use 0 16 gal/lbs <br /> 116 gal • 0 16 gal/lbs = 18 5 gallons of gasoline <br /> 29 August to 30 September 1996 <br /> ' using C = 1,350 pg/1 = 0 001350 kg/m3 <br /> Q = 70 cfm = 118 9 m3/hr <br /> ' t= 1993hr <br /> 0 001350 . 118 9 • 199 3 = 32 0 kg of gasoline <br /> = 70 5 lbs of gasoline <br /> = 113 gallons of gasolene <br /> ' 30 September to 30 October 1996 <br /> using C = 910 µg/1 = 0 000910 kg/m3 <br /> Q = 70 cfm= 1189ml/hr <br /> t= 624 8 hr <br /> 0 000910 . 118 9 • 624 8 = 67 6 kg of gasoline <br /> = 149 lbs of gasoline <br /> =23.8 gallons of gasoline <br />