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MASS CALCULATION: <br /> VOLUME OF EXTRACTED HYDROCARBONS (Gasoline) <br /> Art& Artists <br /> 204 East Lodi Avenue, Lodi, California <br />' The hydrocarbon mass removed during the operating period can be calculated using the following <br />' equation M= C•Q•t <br /> where M= cumulative mass recovered (kg) <br />' C =vapor concentration (kg/m3) <br /> Q = extraction flow rate (m3/hr) <br /> t= operational period <br />' 30 April to 23 May 1996 <br />' using C = 1,925 pg/1 = 0 001925 kg/m3 <br /> Q = 70 cfm= 118 9 m3/hr <br /> t= 5074hr <br />' 0 001925 • 118 9 . 507 4 = 116 kg of gasoline <br /> 116 kg • 2 2046 lbs/kg =256 lbs of gasoline <br /> to convert lbs of gasoline to gallons of gasoline, use 0 16 gal/lbs <br /> 256 gal • 0 16 gal/lbs =41 gallons of gasoline <br />' 23 May to 28 June 1996 <br /> ' using C = 1,850 µg/1 = 0 001850 kg/m3 <br /> Q = 70 cfm= 1189ml/hr <br /> t= 901 8hr <br /> ' 0 001850 • 118 9 . 901 8 = 198 kg of gasoline <br /> = 437 lbs of gasoline <br /> = 70 gallons of gasoline <br /> ' 28 June to 31 July 1996 <br /> using C = 1,015 µg/1 = 0 001015 kg/m3 <br /> ' Q = 70 cfm = 118 9 M3/hr <br /> t= 7979hr <br /> ' 0 001015 • 118 9 . 797 9 = 96 3 kg of gasoline <br /> • =212 lbs of gasoline <br /> =34 gallons of gasoline <br />