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Nitrate Mass Balance Calculation <br /> Schuler Property <br /> Existing 4 Bedroom Residence <br /> Data Input: <br /> Effluent Quantity(Q): 560 gals/day <br /> Effluent Stream(N,H): 35.00 mg/L-N <br /> Site Area(A): 2.27 Acres <br /> Concentration Rain(Nb): 1.00 mg/L-N <br /> Denitrification(d): 35.0% <br /> Deep Perc.of Rain(R): 1.01 in/yr <br /> Result: <br /> Mass Balance(N j: 17.7 mg&-N <br /> MCL Drinking Water Nitrate as N: 10.0 mg/L-N <br /> Percent of MCL Nitrate as N 177% <br /> Waste Loading(W): 3.32in/yr <br /> Equations: <br /> Find!W) <br /> (W) jrL = (Q) " x 1 W x 365 day x 1 acre x 12-1[L x 1 <br /> yr day 7.48 gal 1 year 43,560 ftz 1 ft (A)acre <br /> 3.32 in/yr(site)=560 gaUday x(1 cu-ft/7.48 gals)x(365 days/1 year)x(1 acre 143,560 sq-ft)x(12 in/1 ft)x(1 site/2.27 acres) <br /> N,= WN,,(1-d)+RNL <br /> W+R Hantzsche-Fennemore Equation(Nc) <br /> 17.67 mgiL-N=((3.32 in/yr x 35 mg/L-N x(1-0.35))+(1.01 in/yr x 1 mg/L-N))/(3.32 in/yr+1.01 in/yr) <br /> Variables: <br /> Nc=Average nitrate-N concentration(mgA)of combined effluent and rainfall percolate(17.67 mg/L-N). <br /> W=Uniform waste water loading for study area(in/yr)(3.32 inches/year). <br /> Nw=Total nitrate-N concentration of waste water percolate(35 mgiL-N). <br /> d=Fraction of nitrate-N loss due to denitrification in the sal(35%). <br /> R=Uniform deep percolation of rainfall(1.01 in/yr). <br /> Nb=Background nitrate-N concentration of rainfall(1 mg/L-N). <br /> Assumptions: <br /> 1. Total nitrogen concentration of waste stream based on estimate of 35 mg/L-N. <br /> 2. Fraction of nitrate-N loss due to denitrification in the sal is assumed to be 35%. <br /> 3. Estimated deep percolation of rainfall is 1.01 in/yr,see deep percolation of rain worksheet. <br /> 4. Assume background nitrate-N concentration of rainfall is 1 mg/L-N. <br /> Irerracon <br />