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t <br /> Vapor Extraction System Sample Calculations <br /> Moore Petroleum,Inc.,5491 'T"Street,Banta,CA <br /> t � � <br /> i <br /> VAPOR EXTRACTION SAMPLE CALCULATIONS <br /> j Calculating Daily Extraction Rates <br /> Once given the vapor analytical results in ug/1 and the corresponding system flow rate for that <br /> sampling event in cubic feet per minute(CFM), a daily extraction rate may be calculated in <br /> pounds per day(1b./day). <br /> The sample calculations will be focused on the sampling event which occurred on September 19, <br /> 1995. This sampling event yielded concentrations of total petroleum hydrocarbons(TPH), as <br /> Lgasoline, at 1,500 ug/l, and benzene concentrations at 39 ug/1. The system flow rate on this day <br /> h was 10 CFM. <br /> i <br /> The method for calculating daily extraction rates is to take the analytical concentrations which are <br /> reported in ug/1 and, using standard conversions, convert this value to units of pounds per cubic <br /> rfoot. This value may then be multiplied by the system flow rate on the day the sample was <br /> L collected, in CFM, and then converted to units of days. The result will be the daily extraction rate <br /> in lb./day. An example of this method is as follows: <br /> i <br /> µg 28.3171 1 Ib ft3 1440 min lb <br /> concentration ( 7 )" ft 3 x 4.54x10 gµg Xow rate ( )x =extraction rateO <br /> Min daIf this method is applied to the TPH, as gasoline, concentrations, the following daily extraction <br /> rate results: <br /> 1,500 µg x 28.317 l x 1 lb - x 10 ft3 X 1440 min= 1.3 lb TPH,as gasoline <br /> l ft 3 4.54x108 99 mm day day <br /> This method may also be applied to the benzene concentrations present in the vapor sample: <br /> µg 28.317 l 1 lb ft 3 1440 min lb <br /> 39 —x x X10 X 0.035 Benzene <br /> l ft 3.. 4.54x10 8µg min dam' day <br /> Once the daily extraction rates are known,the cumulative quantities of TPH, as gasoline, and <br /> benzene can be calculated. It will be assumed that the average daily extraction rate for a <br /> i` particular period will lie somewhere between the most recent daily extraction rate and the <br /> previously calculated daily extraction rate. It will be assumed that a sufficient approximation of <br /> the average daily extraction rate for a particular period of time will be the most recent daily <br /> extraction rate averaged with the previously calculated daily extraction rate. <br />