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Adsorbed Gasoline Mass-Volume Calculations • GREWAL'S MARKET 4100 East Fremont Street, Stockton CA Assumptions: • Utilizing Figures 5,7 and 9,the mass distribution of gasoline concentrations greater than 1,000 mg/kg can be approximated utilizing the equation for a coned-ellipse shape. The volume of a coned ellipse can be calculated by the formula: V,•.�=(long diam.)(short diam.)(0.7854)(1is height),where"a"is the long diameter of the coned ellipse, "b" is the short diameter and"c"is the height. The mass distribution of gasoline concentrations greater than 1.0 mg/kg can be approximated utilizing the equation for a cylindrical ellipse. The volume of a cylindrical ellipse can be calculated by the formula: ' Vmm=(long diam.)(short diam.)(0.7854)(height),where"a"is the long diameter of the cylindrical ellipse, "b"is the short diameter and"c"is the height. The average TPH-g concentration was utilized for gasoline-impacted area greater than 1,000 milligrams per kilogram ' (mg/kg)and for the gasoline-impacted area greater than 1 mg/kg;the average was calculated by summing the detected TPH-g concentrations for each area and dividing by the total number of detections. The average TPH-g concentration for the area greater than 1,000 mg/kg was calculated to be 1,900 mg/kg;the average TPH-g concentration for the area greater than 1 mg/kg was calculated to be 165 mg/kg. 10 GASOLINE-IMPACTED AREA GREATER THAN 1,000 MG/KG -Approximate volume of gasoline-impacted ' Soil(VGA5JOOa): The estimated coned ellipse shape for gasoline-impacted area greater than 1,000 mg/kg: a z 28 ft,b = 10 ft,c= 10.5 ft tVGAsjaao=(28 ft)(10#1)(0.7854)(1/3 10.5 ft)4 770 fl(lyd3/27f) R 28.5 yd' Converting 28.5 yd3 to cm3(i.e. lyd3=764,555cm3)yields approximately 21,789,818 cm3.Using 1.9 g/cm3 as the weight ' of soil,the total weight of contaminated soil is approximately 41,400,653 g. Using 1,900 mg/kg as the"average"concentration in the area of TPH-g impacted soil,the mass can be calculated to be: ' weight of soil •average concentration -*41,400,653 g • 0.00 1900=78,661 g of gasoline ' Converting grams of gasoline to volume of gasoline(gallons)using density of gasoline equal to 0.75 (estimate) 78,661 g of gasoline 0.75 g/cm'= 104,882 crn3 104,882 cm3 - (1 gallon 3,785 cm3) = 27.7 gallons of gasoline Converting gallons of gasoline to pounds of gasoline yields: ' 27.7 gallons of gas-0.16 gal(estimate)of gas/lbs. of gas = 173 pounds of gasoline 0 Advanced GeoEnvironmental,Inc.