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APPENDIX F <br /> DISSOLVED TPH-g VOLUME ASSUMPTIONS AND CALCULATIONS <br /> PAGE 7 OF 7 <br /> Multiplying M50post bythe hydrocarbon concentration yields the approximate mass of dissolved hydrocarbons <br /> in the saturated portion of the ellipse cylinder: <br /> Msoposi(101,770 lbs)(0.000000525)=0.05 lbs TPH-g <br /> Dividing M50..,by the weight of one gallon of gasoline, 6.25 lbs/gallon, will yield the volume of TPH-g <br /> dissolved into the ground water of the ellipse cylinder: <br /> V5011o1=(M5o pus)/6.251b/gal)=0.051bs/6.25lbs/gal=0.008 gallons of dissolved TPH-g <br /> Combining the tots olume of dissolved TPH, iTpcted POST-REMEDIATION gro�water yields <br /> approximatel con an estimated 0.02 gallons of TPH-g,equivalent to 0.13 pounds of TPH-g. <br /> �T3 <br /> 2 G y <br /> WAfW <br /> 0 k'� <br /> 00 <br /> 5 ( <br />