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APPENDIX F <br /> DISSOLVED TPH-g VOLUME ASSUMPTIONS AND CALCULATIONS <br /> PAGE 2 OF 7 <br /> Multiplying Mi00000 by the hydrocarbon concentration yields the approximate mass of dissolved <br /> hydrocarbons in the saturated portion of the ellipse: <br /> Mi00000(501,5051bs)(0.000136667)=68.5 lbs of dissolved TPH-g <br /> Dividing M,00000 by the weight of one gallon of gasoline,6.25 lbs/gallon,will yield the approximate volume <br /> of TPH-g dissolved into the ground water of the inner ellipsoid: <br /> Vi00000=(Mm0000)/6.25lb/gal)=68.5/6.25 lbs/gal= 11 gallons of dissolved TPH-g <br /> 2) For the estimated 10,000 µg/1 ellipse cylinder, a=38 ft,b= 31 ft, and thickness c=20 ft <br /> Utilizing TPH-g data from well MW-1, the 100,000 µg/1 contour line and the 10,000 µg/1 contour line <br /> (Figure 9), the average pre-remediation TPH-g concentration is estimated to be 59,667 ug/l(equivalent to <br /> 0.000059667 g/ml).A ml is very nearly equivalent to a cubic centimeter ofwater,which by definition equals <br /> one gram, this concentration is essentially unitless. <br /> The area of the ellipse is given by: A10000=7r(38)(3 1)= 3,701 ft- A100000=2,695.7 fP <br /> The volume of the ellipse cylinder is given by: V,0000=Ai0000 x c=2695.7 W x 20 ft =53,914 ft' <br /> Water occupies the porosity in the soil,which is estimated to be 40%of the soil volume,so the total volume <br /> of water in the saturated portion of the ellipse is approximated by: V,0000=(0.40)(53,914 ft') =21,566 ft' <br /> One ft' is equal to 7.48 gallons, so the volume of the water in the ellipse is given by: <br /> V10000=(21,566 ft')(7.48 gal/ft') = 161,314 gallons <br /> One gallon of water weighs 8.337 lbs/gal, so the mass of the water in the ellipse is given by: <br /> Mi0000= (161,314 gallons)(8.337 lb/gal)= 1,344,875 lbs <br /> Multiplying Mi0000 by the hydrocarbon concentration yields the approximate mass ofdissolved hydrocarbons: <br /> M,0000( 1,344,875 lbs)(0.000059667)=80.2 lbs of dissolved TPH-g <br /> Dividing M10000 by the weight of one gallon of gasoline,6.25 lbs/gallon,will yield the approximate volume <br /> of TPH-g dissolved into the ground water of the inner-middle ellipsoid: <br /> V10000=(MI0000)/6.251b/gal)=80.21bs/6.25 lbs/gal=12.8 gallons of dissolved TPH-g <br />