Laserfiche WebLink
Mass-Volume Calculations Of Extracted Gasoline Hydrocarbons <br /> SIERRA LUMBER-375 West Hazelton Avenue, Stockton, CA <br /> Assumptions <br /> • Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE pilot test (Table 5), the average concentration of extracted gasoline hydrocarbons at the site can be <br /> approximated <br /> The hydrocarbon mass removed during the operating period can be calculated using the following equation <br /> M=C• Q• t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kghn3) <br /> I Q=extraction flow rate(m/hr) <br /> t=operationaI period(hrs) <br /> The average valet TPH-g concentration and average flow rates during each tune interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br /> I1. 20 March 2003 to 15 April 2003 <br /> The average analytical TPH-g concentration for this time interval was determined to be 234,ug/l(03-20-03= 140,ug/L <br /> lie and 04-15-03 = 57,ug/L, avg =98 5 pg/L) The average flow rates dunng this time was calculated at 0 40 inches of <br /> water or approximately 34 cubic feet per minute(table 6),the operational period was equal to 624 hours of running time <br /> C = 98 5#g/l=0 0000985 kg/m' <br /> Q z 0 40 inches water H 34 ft/mm <br /> t=624 hours(26 days) <br /> Converting Q to ni/hour yields <br /> Q=(34 ft'/rmn) •(60 nun/hour) •(0 0283168m3/ft')=57 77 m3/hour <br /> M=C • Q • t=(0 0000985 kg/m) •(57 77 m'/hour) • (624 hours)=3 55 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> I 3 55 kg of gas - 2 2046 lbs of gas/kg of gas=7.83 lbs of gasoline <br /> 7 83 lbs gas/26 days=0.30 lbs/clay <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 7 83 lbs of gas • 0 16 gal of gas/lbs of gas 1.25 gallons of gasoline <br />