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ARCHIVED REPORTS_XR0003762
EnvironmentalHealth
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EHD Program Facility Records by Street Name
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H
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HAZELTON
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375
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2900 - Site Mitigation Program
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PR0540905
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ARCHIVED REPORTS_XR0003762
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Last modified
2/3/2020 10:10:17 AM
Creation date
2/3/2020 9:06:33 AM
Metadata
Fields
Template:
EHD - Public
ProgramCode
2900 - Site Mitigation Program
File Section
ARCHIVED REPORTS
FileName_PostFix
XR0003762
RECORD_ID
PR0540905
PE
2960
FACILITY_ID
FA0023406
FACILITY_NAME
SIERRA LUMBER MANUFACTURERS
STREET_NUMBER
375
Direction
W
STREET_NAME
HAZELTON
STREET_TYPE
AVE
City
STOCKTON
Zip
95205
APN
147120808
CURRENT_STATUS
01
SITE_LOCATION
375 W HAZELTON AVE
P_LOCATION
01
QC Status
Approved
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SJGOV\sballwahn
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EHD - Public
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Mass-Volume Calculations Extracted Gasoline Hydrocarbons <br /> � VlClltiOf Edroca <br /> y <br /> SIERRA LUMBER- 375 West Hazelton Avenue, Stockton, CA <br />' Assumptions <br />' Utilizing analytical data collected from au samples(Table 4)and from field measurements collected during the <br /> SVT, pilot test (Table 5), the average concentration of extracted gasoline hydrocarbons at the site can be <br /> approximated <br />' The hydrocarbon mass removed during the operating period can be calculated using the following equation <br />' M=C- Q - t <br /> where M=cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m') <br />' Q=extraction flow rate(m'/hr) <br /> t=operational period(hrs) <br />' The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br />' 1 11 September 2002 to 30 October 2002 <br /> The average analytical TPH-g concentration for this time interval was determined to be 105,ug/l(09-11-02=80,ug/L and <br /> 10-30-02= 130,ug/L,avg = 105,ug/L) The average flow rates during this time was calculated at 0 40 inches of water <br /> or approximately 36 cubic feet per minute(table 6), the operational period was equal to 1,176 hours of running time <br /> C = 105 ug/l=0 000105 kg/m' <br /> Q = 0 40 niches water = 36 ft' <br /> /min <br /> t= 1,176 hours <br /> Converting Q to m3/hour yields <br /> Q=(36 ft'/min) -(60 nun/hour) -(0 0283168m'/ft3)=61 16 m'/hour <br /> M=C- Q - t=(0 000105 kg/m') -(61 16 m3/hour) - (1,176 hours)=7 55 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 7 55 kg of gas - 2 2046 lbs of gas/kg of gas=16 65 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 16 65 lbs of gas - 0 16 gal of gas/lbs of gas = 2 66 gallons of gasoline <br /> I <br /> 1 <br />
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