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Mass-Volume Calculations Of Extracted Gasoline Hydrocarbons <br /> • SIERRA LUMBER- 375 West Hazelton Avenue, Stockton, CA <br /> 1 Assumptions <br />' Utilizing analytical data collected from air samples(Table 4)and from field measurements collected during the <br /> SVE pilot test (Table 5), the average concentration of extracted gasoline hydrocarbons at the site can be <br /> approximated <br />' The hydrocarbon mass removed during the operating period can be calculated usmg the following equation <br />' — M=C• Q • t <br /> where M—cumulative mass recovered(kg) <br /> C=vapor concentration(kg/m3) <br />' Q=extraction flow rate(m3/hr) <br /> t=operational period(hrs) <br />' The average inlet TPH-g concentration and average flow rates during each time interval were utilized for calculating the <br /> approximate mass/volume of extracted gasoline hydrocarbons <br />' 1. 11 March to 23 April 2002 <br /> The average analytical TPH-g concentration for this time interval was determined to be 335,ug/l(03-11-02=480,ug/L <br /> and 0423-02 = 190µg/L, avg =335,ug/L) The average flow rates during this time was calculated at 0-37 inches of <br /> water or approximately 35 cubic feet per minute (table 6),the operational period was equal to 1,032 hours of mmnmg <br /> time <br /> C = 335 pgll=0 000335 kg/m' <br /> Q = 0 37 inches water = 35 fl'/nun <br />' t= 1,032 hours <br /> Converting Q to m3/hour yields <br /> Q=(35 fi'/nun)-(60 min/hour) -(0 0283168m3/if)=59 47 ni/hour <br /> M=C- Q- t=(0 000335 kg/m')-(59 47 m3/hour) • (1,032 hours)=20 56 kg of gasoline <br /> Converting kg of gasoline to pounds of gasoline yields <br /> 20 56 kg of gas• 2 2046 lbs of gas/kg of gas=45 33 lbs of gasoline <br /> Converting pounds of gasoline to gallons of gasoline yields <br /> 45 33 lbs of gas - 0 16 gal of gas/lbs of gas = 7 25 gallons of gasoline <br /> I <br /> I <br />